F(x)=11x^2-5x+13

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Solution for F(x)=11x^2-5x+13 equation: 



(F)=11F^2-5F+13

We move all terms to the left:

(F)-(11F^2-5F+13)=0

We get rid of parentheses

-11F^2+F+5F-13=0

We add all the numbers together, and all the variables

-11F^2+6F-13=0

a = -11; b = 6; c = -13;
Δ = b2-4ac
Δ = 62-4·(-11)·(-13)
Δ = -536
Delta is less than zero, so there is no solution for the equation

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